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(F)=-5+8F^2
We move all terms to the left:
(F)-(-5+8F^2)=0
We get rid of parentheses
-8F^2+F+5=0
a = -8; b = 1; c = +5;
Δ = b2-4ac
Δ = 12-4·(-8)·5
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{161}}{2*-8}=\frac{-1-\sqrt{161}}{-16} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{161}}{2*-8}=\frac{-1+\sqrt{161}}{-16} $
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